When selecting a single card from a standard deck of 52 cards, what is the probability of drawing either a diamond or a face card?
P(A or B) = P(A) + P(B) – P(A and B)
Let A be the event of drawing a diamond → \(\frac{13}{52}\)
Let B be the event of drawing a face card → \(\frac{12}{52}\)
There are three cards that are both a diamond and a face card → \(\frac{3}{52}\)
\(P(A\ or\ B) = \frac{13}{52}\ + \frac{12}{52}\ −\ \frac{3}{52} = \frac{11}{26}\)