**When selecting a single card from a standard deck of 52 cards, what is the probability of drawing either a diamond or a face card?**

*P*(*A* or *B*) = *P*(*A*) + *P*(*B*) – *P*(*A* and *B*)

Let* A *be the event of drawing a diamond → \(\frac{13}{52}\)

Let *B* be the event of drawing a face card → \(\frac{12}{52}\)

There are three cards that are both a diamond and a face card → \(\frac{3}{52}\)

\(P(A\ or\ B) = \frac{13}{52}\ + \frac{12}{52}\ −\ \frac{3}{52} = \frac{11}{26}\)